(C) The magnetic energy density $(u)$ stored in a magnetic field is given by the formula:$u = \frac{B^2}{2\mu_0}$Given:$B = 0.6 \ T$$\mu_0 = 4\pi \tim

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(C) The magnetic energy density $(u)$ stored in a magnetic field is given by the formula:$u = \frac{B^2}{2\mu_0}$Given:$B = 0.6 \ T$$\mu_0 = 4\pi \times 10^{-7} \ T \cdot m/A \approx 12.56 \times 10^{-7} \ T \cdot m/A$Substituting the values:$u = \frac{(0.6)^2}{2 \times 4 \times 3.14 \times 10^{-7}}$$u = \frac{0.36}{25.12 \times 10^{-7}}$$u = \frac{0.36}{2.512 \times 10^{-6}}$$u \approx 0.1433 \times 10^6 \ J/m^3$$u = 1.43 \times 10^5 \ J/m^3$

Class 12 Physics Moving Charges and Magnetism Ampere’s circuital law and its application (Solenoid and Toroid)

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For a long current-carrying solenoid,the magnetic field inside is $0.6 \ T$. The magnetic energy per unit volume is . . . . . . .

GUJCET 2021 All GUJCET

A
$5.23 \times 10^4 \ J/m^3$
B
$2.86 \times 10^4 \ J/m^3$
C
$1.43 \times 10^5 \ J/m^3$
D
zero

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Moving Charges and Magnetism

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Ampere’s circuital law and its application (Solenoid and Toroid)

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