$A$ voltmeter has a resistance of $G \ \Omega$ and a range of $V \ \text{volt}$. The resistance required in series to convert it into a voltmeter of range $nV \ \text{volt}$ is . . . . . . .

$A$ milliammeter of resistance $40 \Omega$ has a range $0-30 \text{ mA}$. What will be the resistance used in series to convert it into a voltmeter of range $0-15 \text{ V}$ (in $\Omega$)?

$A$ galvanometer has $36\,\Omega$ resistance. If a $4\,\Omega$ shunt is added to this,the fraction of current that passes through the shunt is

When a galvanometer is shunted with a $4\,\Omega$ resistance,the deflection is reduced to one-fifth. If the galvanometer is further shunted with a $2\,\Omega$ wire,the further reduction in the deflection will be (the main current remains same).

$A$ galvanometer of resistance $40\,\Omega$ gives a deflection of $5\, \text{divisions}$ per $mA$. There are $50\, \text{divisions}$ on the scale. The maximum current that can pass through it when a shunt resistance of $2\,\Omega$ is connected is ................ $mA$.

An ammeter of $100 \, \Omega$ resistance gives full-scale deflection for a current of $10^{-5} \, A$. The shunt resistance required to convert it into an ammeter of $1 \, A$ range will be: