$A$ galvanometer has $36\,\Omega$ resistance. If a $4\,\Omega$ shunt is added to this,the fraction of current that passes through the shunt is

  • A
    $\frac{1}{4}$
  • B
    $\frac{1}{9}$
  • C
    $\frac{1}{10}$
  • D
    $\frac{9}{10}$

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Similar Questions

This question has Statement-$I$ and Statement-$II$. Of the four choices given after the statements,choose the one that best describes the two statements.
Statement-$I$: Higher the range,greater is the resistance of an ammeter.
Statement-$II$: To increase the range of an ammeter,an additional shunt needs to be used across it.

The resistance of a galvanometer is $25\,\Omega$ and it requires $50\,\mu A$ for full-scale deflection. The value of the shunt resistance required to convert it into an ammeter of $5\,A$ range is:

$A$ voltmeter has a resistance of $2000 \, \Omega$ and it can measure up to $2 \, V$. If we want to increase its range to $10 \, V$, then the required resistance in series will be ........... $\Omega$.

$A$ galvanometer having a coil resistance of $100 \ \Omega$ gives a full-scale deflection when a current of $1 \ mA$ is passed through it. The value of the shunt resistance,which can convert this galvanometer into an ammeter giving a full-scale deflection for a current of $10 \ A$,is: ...... $\Omega$

$A$ galvanometer of resistance $50 \Omega$ gives a full-scale deflection for a current of $5 \times 10^{-4} \text{ A}$. The resistance that should be connected in series with the galvanometer to read $3 \text{ V}$ is: (in $\Omega$)

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