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(C) The reaction of formaldehyde $(HCHO)$ with a Grignard reagent $(RMgX)$ followed by acid hydrolysis yields a primary alcohol.In this case,the produ

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$CH_{3}MgI$

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(C) The reaction of formaldehyde $(HCHO)$ with a Grignard reagent $(RMgX)$ followed by acid hydrolysis yields a primary alcohol.In this case,the product is ethanol $(C_{2}H_{5}OH)$,which contains two carbon atoms.Since formaldehyde provides one carbon atom,the Grignard reagent must provide the other methyl group $(CH_{3})$.Therefore,the reagent $X$ is methylmagnesium iodide $(CH_{3}MgI)$.The reaction is: $HCHO + CH_{3}MgI$ $\rightarrow CH_{3}CH_{2}OMgI$ $\xrightarrow{H_{3}O^{+}} CH_{3}CH_{2}OH + Mg(OH)I$.

$HCHO$ was treated with a reagent $X$. The product formed upon hydrolysis in the presence of an acid gave $C_{2}H_{5}OH$. The reagent $X$ is

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