Mn^{2+} compounds are more stable than Fe^{2+ | vedclass

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(A) The electronic configuration of $Mn^{2+}$ is $[Ar] 3d^5$. This configuration is half-filled,which provides extra stability.The electronic configur

Vedclass · Accepted Answer

$Mn^{2+}$ is more stable with high $3rd$ ionization energy.

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(A) The electronic configuration of $Mn^{2+}$ is $[Ar] 3d^5$. This configuration is half-filled,which provides extra stability.The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$.Oxidation to the $+3$ state involves the removal of an electron from the $d$-subshell. For $Mn^{2+}$,removing an electron disrupts the stable half-filled $d^5$ configuration,requiring a very high third ionization energy.For $Fe^{2+}$,removing an electron from the $3d^6$ configuration results in a stable $3d^5$ configuration,which requires less energy.Therefore,$Mn^{2+}$ is more resistant to oxidation to the $+3$ state compared to $Fe^{2+}$.

$Mn^{2+}$ compounds are more stable than $Fe^{2+}$ compounds towards oxidation to their $+3$ state,because

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