A student has to answer 10 questions,choosing | vedclass

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Question

(C) Given,total questions in part $A = 6$ and total questions in part $B = 7$. To choose $10$ questions with at least $4$ from each part,the possible

Vedclass · Accepted Answer

$266$

Vedclass · Answer

(C) Given,total questions in part $A = 6$ and total questions in part $B = 7$. To choose $10$ questions with at least $4$ from each part,the possible combinations are: $1$. $4$ from part $A$ and $6$ from part $B$ $2$. $5$ from part $A$ and $5$ from part $B$ $3$. $6$ from part $A$ and $4$ from part $B$ Total ways = $({ }^{6}C_{4} 	imes { }^{7}C_{6}) + ({ }^{6}C_{5} 	imes { }^{7}C_{5}) + ({ }^{6}C_{6} 	imes { }^{7}C_{4})$ $= (15 	imes 7) + (6 	imes 21) + (1 	imes 35)$ $= 105 + 126 + 35 = 266$

$A$ student has to answer $10$ questions,choosing at least $4$ from each of the parts $A$ and $B$. If there are $6$ questions in part $A$ and $7$ in part $B$,then the number of ways the student can choose $10$ questions is:

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