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(A) The work done during expansion is given by the formula $W = -P_{ext} \Delta V$. Since the gas is expanding against an external pressure,the work d

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$10^{2} \ kJ$

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(A) The work done during expansion is given by the formula $W = -P_{ext} \Delta V$. Since the gas is expanding against an external pressure,the work done by the gas is $W = P_{ext} \Delta V$. Given $P_{ext} = 10^{5} \ Nm^{-2}$,$V_{1} = 1 \ m^{3}$,and $V_{2} = 2 \ m^{3}$. $\Delta V = V_{2} - V_{1} = 2 \ m^{3} - 1 \ m^{3} = 1 \ m^{3}$. $W = 10^{5} \ Nm^{-2} 	imes 1 \ m^{3} = 10^{5} \ J$. Converting to kilojoules,$10^{5} \ J = 100 \ kJ = 10^{2} \ kJ$.

$A$ gas expands from a volume of $1 \ m^{3}$ to a volume of $2 \ m^{3}$ against an external pressure of $10^{5} \ Nm^{-2}$. The work done by the gas will be

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