A modulated signal is given by C_m(t) = A_c s | vedclass

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Question

(D) The modulation index $\mu$ is defined as the ratio of the amplitude of the modulating signal $(A_m)$ to the amplitude of the carrier wave $(A_c)$:

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≤ $1$

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(D) The modulation index $\mu$ is defined as the ratio of the amplitude of the modulating signal $(A_m)$ to the amplitude of the carrier wave $(A_c)$: $\mu = \frac{A_m}{A_c}$.To avoid distortion in the modulated signal (specifically over-modulation),the amplitude of the modulating signal must not exceed the amplitude of the carrier wave.Therefore,the condition for no distortion is $A_m \leq A_c$.Dividing both sides by $A_c$,we get $\frac{A_m}{A_c} \leq 1$.Thus,$\mu \leq 1$.

$A$ modulated signal is given by $C_m(t) = A_c \sin \omega_c t + \mu A_c \sin \omega_m t \sin \omega_c t$,where $\mu$ is the modulation index. To keep the signal without distortion,the value of $\mu$ should be

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