A straight wire of resistance R is bent into | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) When a wire of resistance $R$ is bent into a square, each side has a resistance of $R/4$.Let the corners of the square be $A, B, C,$ and $D$ in or

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(A) When a wire of resistance $R$ is bent into a square, each side has a resistance of $R/4$.Let the corners of the square be $A, B, C,$ and $D$ in order. The cell is connected between adjacent corners $A$ and $D$.The path $A-B-C-D$ has a total resistance of $R/4 + R/4 + R/4 = 3R/4$.The direct path $A-D$ has a resistance of $R/4$.These two paths are in parallel across the $12 	ext{ V}$ source.The potential difference across any diagonal (e.g., $A$ to $C$) is the potential drop across the path $A-B-C$.The current $I_1$ flowing through the branch $A-B-C$ is given by $I_1 = V / R_{branch} = 12 / (3R/4) = 16/R$.The potential difference across the diagonal $AC$ is the voltage drop across the resistors $AB$ and $BC$ in series:$V_{AC} = I_1 	imes (R/4 + R/4) = (16/R) 	imes (R/2) = 8 	ext{ V}$.

$A$ straight wire of resistance $R$ is bent into the shape of a square. $A$ cell of emf $12 \text{ V}$ is connected between two adjacent corners of the square. The potential difference across any diagonal of the square is (in $\text{ V}$)

Similar Questions

The potential difference across the $8\ \Omega$ resistance is $48\ V$ as shown in the figure. The value of the potential difference across points $X$ and $Y$ will be ............... $V$.

The terminal voltage of the battery, whose emf is $10 \, V$ and internal resistance is $1 \, \Omega$, when connected through an external resistance of $4 \, \Omega$ as shown in the figure is: (in $V$)

$A$ potential divider is used to give outputs of $4\, V$ and $8\, V$ from a $12\, V$ source. Which combination of resistances $(R_1, R_2, R_3)$ gives the correct voltages? Find the ratio $R_1 : R_2 : R_3$.

Electric bulbs rated $50\, W$ - $100\, V$ glowing at full power are to be used in parallel with a battery of $120\, V$ and internal resistance $10\,\Omega$. The maximum number of bulbs that can be connected so that they glow at full power is:

Find the current passing through the battery immediately after the key $(K)$ is closed. It is given that initially all the capacitors are uncharged. (Given that $E = 5 \, V$, $R = 6 \, \Omega$) (in $A$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module