A large number of positive charges,each of ma | vedclass

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(A) The charges are placed at $x = 0, \pm 1 	ext{ cm}, \pm 2 	ext{ cm}, \pm 3 	ext{ cm}, \dots$Since the spherical surface has a radius of $2.5 	e

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$\frac{5 q}{\varepsilon_0}$

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(A) The charges are placed at $x = 0, \pm 1 	ext{ cm}, \pm 2 	ext{ cm}, \pm 3 	ext{ cm}, \dots$Since the spherical surface has a radius of $2.5 	ext{ cm}$ and is centered at the origin,it encloses the charges located at $x = 0, \pm 1 	ext{ cm},$ and $\pm 2 	ext{ cm}$.The total number of charges enclosed is $1$ (at origin) $+ 2$ (at $\pm 1 	ext{ cm}$) $+ 2$ (at $\pm 2 	ext{ cm}$) $= 5$ charges.Thus,the total charge enclosed by the sphere is $Q_{	ext{enclosed}} = 5q$.According to Gauss's Law,the total electric flux $\phi$ through the spherical surface is given by $\phi = \frac{Q_{	ext{enclosed}}}{\varepsilon_0}$.Therefore,$\phi = \frac{5q}{\varepsilon_0}$.

$A$ large number of positive charges,each of magnitude $q$,are placed along the $X$-axis at the origin and at every $1 \text{ cm}$ distance in both directions. The electric flux through a spherical surface of radius $2.5 \text{ cm}$ centered at the origin is

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