IUPAC names of the given compounds (I) and (I | vedclass

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(C) For compound $(I)$: The longest carbon chain containing the nitro group has $4$ carbons. Numbering starts from the end closer to the nitro group.

Vedclass · Accepted Answer

$2-$Nitro$-1-$phenylbutane; $1-$ethyl$-1-$methyl$-2-$propylcyclohexane

Vedclass · Answer

(C) For compound $(I)$: The longest carbon chain containing the nitro group has $4$ carbons. Numbering starts from the end closer to the nitro group. The phenyl group is at position $1$. Thus,the name is $2-$nitro$-1-$phenylbutane.For compound $(II)$: The ring is cyclohexane. Substituents are at positions $1$ and $2$. According to alphabetical order,ethyl comes before methyl and propyl. Numbering is done to give the lowest locants to substituents. The correct numbering gives $1-$ethyl$-1-$methyl$-2-$propylcyclohexane.

$IUPAC$ names of the given compounds $(I)$ and $(II)$ are respectively

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