$A$ polyatomic gas with $n$ degrees of freedom has a mean kinetic energy per molecule given by (if $K$ is Boltzmann's constant):

$A$ polyatomic gas with $n$ degrees of freedom has a mean energy per molecule given by (where $k$ is Boltzmann's constant and $T$ is temperature).

The kinetic energy per gram mole for a diatomic gas at room temperature is:

The specific heats,$C_P$ and $C_V$ of a gas of diatomic molecules,$A$,are given (in units of $J\, mol^{-1}\, K^{-1}$) by $29$ and $22$,respectively. Another gas of diatomic molecules,$B$,has the corresponding values $30$ and $21$. If they are treated as ideal gases,then:

How many rotational degrees of freedom does a rigid diatomic molecule have?

The ratio of specific heats at constant pressure and at constant volume is $\gamma$. To find out the degree of freedom,the expression is