A force (2 hat{i} + hat{j} - hat{k}) text{ N} | vedclass

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(B) Given force vector $\vec{F} = (2 \hat{i} + \hat{j} - \hat{k}) 	ext{ N}$.Initial velocity $\vec{u} = 0 	ext{ ms}^{-1}$.Final velocity $\vec{v} =

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$10$

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(B) Given force vector $\vec{F} = (2 \hat{i} + \hat{j} - \hat{k}) 	ext{ N}$.Initial velocity $\vec{u} = 0 	ext{ ms}^{-1}$.Final velocity $\vec{v} = (4 \hat{i} + 2 \hat{j} - 2 \hat{k}) 	ext{ ms}^{-1}$.Time $t = 20 	ext{ s}$.Using Newton's Second Law, $\vec{F} = m \vec{a} = m \left( \frac{\vec{v} - \vec{u}}{t} ight)$.Rearranging for mass: $m = \frac{\vec{F} \cdot t}{\vec{v} - \vec{u}}$.Since $\vec{v} - \vec{u} = (4 \hat{i} + 2 \hat{j} - 2 \hat{k}) = 2(2 \hat{i} + \hat{j} - \hat{k}) = 2 \vec{F}$.Substituting the values: $m = \frac{\vec{F} \cdot 20}{2 \vec{F}} = \frac{20}{2} = 10 	ext{ kg}$.

$A$ force $(2 \hat{i} + \hat{j} - \hat{k}) \text{ N}$ acts on a body, which is initially at rest. At the end of $20 \text{ s}$, the velocity of the body is $(4 \hat{i} + 2 \hat{j} - 2 \hat{k}) \text{ ms}^{-1}$. The mass of the body is: (in $\text{ kg}$)

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