$A$ wire is stretched $1 \ mm$ by a force $F$. If a second wire of same material,same length and $4$ times the diameter of the first wire is stretched by the same force $F$,then the elongation of the second wire is

  • A
    $\frac{1}{8} \ mm$
  • B
    $8 \ mm$
  • C
    $16 \ mm$
  • D
    $\frac{1}{16} \ mm$

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