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सिद्ध कीजिए कि:
$2 \sin ^{2} \frac{\pi}{6}+\csc ^{2} \frac{7 \pi}{6} \cos ^{2} \frac{\pi}{3}=\frac{3}{2}$

यदि $\sec x + \tan x = 3, x \in (0, \frac{\pi}{2})$ है,तो $\sin x =$

$\tan 67 \frac{1}{2}^{\circ} + \cot 67 \frac{1}{2}^{\circ}$ का मान है

यदि $\cosh x = \frac{\sqrt{14}}{3}$,$\sinh x = \cos \theta$ और $-\pi < \theta < -\frac{\pi}{2}$ है,तो $\sin \theta =$

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