sin (x+y) sec x sec y= | vedclass

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Question

(D) આપણે જાણીએ છીએ કે $\sin (x+y) = \sin x \cos y + \cos x \sin y$.આ કિંમત પદાવલિમાં મૂકતા:$\sin (x+y) \sec x \sec y = (\sin x \cos y + \cos x \sin y)

Vedclass · Accepted Answer

$	an x+	an y$

Vedclass · Answer

(D) આપણે જાણીએ છીએ કે $\sin (x+y) = \sin x \cos y + \cos x \sin y$.આ કિંમત પદાવલિમાં મૂકતા:$\sin (x+y) \sec x \sec y = (\sin x \cos y + \cos x \sin y) \cdot \frac{1}{\cos x} \cdot \frac{1}{\cos y}$$= \frac{\sin x \cos y}{\cos x \cos y} + \frac{\cos x \sin y}{\cos x \cos y}$$= \frac{\sin x}{\cos x} + \frac{\sin y}{\cos y}$$= 	an x + 	an y$

$\sin (x+y) \sec x \sec y=$

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