A ray of light coming from the point (1, 2) i | vedclass

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(A) Let the coordinates of point $A$ be $(a, 0)$.Since the ray is reflected at the $x$-axis,the angle of incidence equals the angle of reflection.Let

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$(13/5, 0)$

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(A) Let the coordinates of point $A$ be $(a, 0)$.Since the ray is reflected at the $x$-axis,the angle of incidence equals the angle of reflection.Let the incident ray from $(1, 2)$ to $(a, 0)$ have slope $m_1 = \frac{2 - 0}{1 - a} = \frac{2}{1 - a}$.The reflected ray from $(a, 0)$ to $(5, 3)$ has slope $m_2 = \frac{3 - 0}{5 - a} = \frac{3}{5 - a}$.By the law of reflection,the angle made with the $x$-axis by the incident ray is $\pi - 	heta$ and by the reflected ray is $	heta$,where $	an 	heta = m_2$ and $	an(\pi - 	heta) = m_1$.Thus,$m_1 = -m_2$.$\frac{2}{1 - a} = -\frac{3}{5 - a}$$2(5 - a) = -3(1 - a)$$10 - 2a = -3 + 3a$$13 = 5a$$a = \frac{13}{5}$.Therefore,the coordinates of $A$ are $(\frac{13}{5}, 0)$.

$A$ ray of light coming from the point $(1, 2)$ is reflected at a point $A$ on the $x$-axis and then passes through the point $(5, 3)$. The coordinates of the point $A$ are

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