$A$ tower subtends angles $\alpha, 2 \alpha$ and $3 \alpha$ respectively at points $A, B$ and $C$,all lying on a horizontal line through the foot of the tower. Then $\frac{A B}{B C}$ is equal to:

  • A
    $\frac{\sin 3 \alpha}{\sin 2 \alpha}$
  • B
    $1+2 \cos 2 \alpha$
  • C
    $2 \cos 2 \alpha$
  • D
    $\frac{\sin 2 \alpha}{\sin \alpha}$

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