$A$ point $C$ with position vector $\frac{3 \bar{a}+4 \bar{b}-5 \bar{c}}{3}$ (where $\bar{a}, \bar{b}$ and $\bar{c}$ are non-coplanar vectors) divides the line segment joining $A$ and $B$ in the ratio $2:1$. If the position vector of $A$ is $\bar{a}-2 \bar{b}+3 \bar{c}$,then find the position vector of $B$.

  • A
    $2 \bar{a}+3 \bar{b}-4 \bar{c}$
  • B
    $2 \bar{a}-3 \bar{b}+4 \bar{c}$
  • C
    $2 \bar{a}+3 \bar{b}+4 \bar{c}$
  • D
    $\bar{a}+3 \bar{b}-4 \bar{c}$

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