$A$ bag contains $7$ green and $5$ black balls. $3$ balls are drawn at random one after the other. If the balls are not replaced,then the probability of all three balls being green is

  • A
    $\frac{343}{1720}$
  • B
    $\frac{21}{36}$
  • C
    $\frac{12}{35}$
  • D
    $\frac{7}{44}$

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