(A) Let the mass of the first part be $m$ and the mass of the second part be $(M - m)$.Heat released by $m \ kg$ of water at $t^{\circ} C$ to become i

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(A) Let the mass of the first part be $m$ and the mass of the second part be $(M - m)$.Heat released by $m \ kg$ of water at $t^{\circ} C$ to become ice at $0^{\circ} C$ is:$Q_1 = m \times c \times (t - 0) + m \times L_f = m \times 1 \times t + m \times 80 = m(t + 80)$.Heat absorbed by $(M - m) \ kg$ of water at $t^{\circ} C$ to become steam at $100^{\circ} C$ is:$Q_2 = (M - m) \times c \times (100 - t) + (M - m) \times L_v = (M - m) \times 1 \times (100 - t) + (M - m) \times 540 = (M - m)(640 - t)$.Equating $Q_1 = Q_2$:$m(t + 80) = (M - m)(640 - t)$$mt + 80m = 640M - Mt - 640m + mt$$80m + 640m = 640M - Mt$$720m = M(640 - t)$$\frac{m}{M} = \frac{640 - t}{720}$.

Class 11 Physics 10-1.Thermometry, Thermal Expansion and Calorimetry Mix Examples-Thermometry, Thermal Expansion and Calorimetry

Difficult

$M \ kg$ of water at $t^{\circ} C$ is divided into two parts so that one part of mass $m \ kg$ when converted into ice at $0^{\circ} C$ would release enough heat to vaporize the other part. Then $\frac{m}{M}$ is equal to (Specific heat of water $= 1 \ cal \ g^{-1} {}^{\circ} C^{-1}$,Latent heat of fusion of ice $= 80 \ cal \ g^{-1}$,Latent heat of steam $= 540 \ cal \ g^{-1}$)

AP EAMCET 2016 All AP EAMCET

A
$\frac{640 - t}{720}$
B
$\frac{720 - t}{640}$
C
$\frac{640 + t}{720}$
D
$\frac{720 + t}{640}$

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10-1.Thermometry, Thermal Expansion and Calorimetry

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Mix Examples-Thermometry, Thermal Expansion and Calorimetry

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AP EAMCET 2016 Paper All AP EAMCET years →

Match List-$I$ with List-$II$.
List-$I$ List-$II$
$(A)$ Heat capacity of body $(I)$ $J kg^{-1}$
$(B)$ Specific heat capacity of body $(II)$ $J K^{-1}$
$(C)$ Latent heat $(III)$ $J kg^{-1} K^{-1}$
$(D)$ Thermal conductivity $(IV)$ $J m^{-1} K^{-1} s^{-1}$

Choose the correct answer from the options given below:

MediumJEE MAIN 2025

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The freezing point of a liquid decreases when pressure is increased,if the liquid:

Easy

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Match the following List-$I$ with List-$II$.
List-$I$ List-$II$
$A$. When ice melts into water $I$. Volume increases
$B$. When water changes into steam $II$. Volume decreases
$C$. Melting point of ice $III$. Increases with increase of pressure
$D$. Boiling point of water $IV$. Decreases with increase in pressure

EasyAP EAMCET 2018

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$A$ metal rod is used as a pendulum. If the room temperature increases by $10^{\circ}C$ and the linear expansion coefficient of the metal is $2 \times 10^{-6} {\circ}C^{-1}$,then the percentage change in the time period of the pendulum is ...... $\%$

Medium

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If $60 \%$ of the kinetic energy of water falling from a $210 \ m$ high waterfall is converted into heat,the rise in temperature of the water at the bottom of the fall is nearly (specific heat of water $= 4.2 \times 10^3 \ J \ kg^{-1} \ K^{-1}$ and $g = 10 \ m/s^2$):

DifficultAP EAMCET 2020

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List-$I$	List-$II$
$(A)$ Heat capacity of body	$(I)$ $J kg^{-1}$
$(B)$ Specific heat capacity of body	$(II)$ $J K^{-1}$
$(C)$ Latent heat	$(III)$ $J kg^{-1} K^{-1}$
$(D)$ Thermal conductivity	$(IV)$ $J m^{-1} K^{-1} s^{-1}$

List-$I$	List-$II$
$A$. When ice melts into water	$I$. Volume increases
$B$. When water changes into steam	$II$. Volume decreases
$C$. Melting point of ice	$III$. Increases with increase of pressure
$D$. Boiling point of water	$IV$. Decreases with increase in pressure

Similar Questions

Match List-$I$ with List-$II$.List-$I$List-$II$$(A)$ Heat capacity of body$(I)$ $J kg^{-1}$$(B)$ Specific heat capacity of body$(II)$ $J K^{-1}$$(C)$ Latent heat$(III)$ $J kg^{-1} K^{-1}$$(D)$ Thermal conductivity$(IV)$ $J m^{-1} K^{-1} s^{-1}$Choose the correct answer from the options given below:

The freezing point of a liquid decreases when pressure is increased,if the liquid:

$A$ metal rod is used as a pendulum. If the room temperature increases by $10^{\circ}C$ and the linear expansion coefficient of the metal is $2 \times 10^{-6} {\circ}C^{-1}$,then the percentage change in the time period of the pendulum is ...... $\%$

If $60 \%$ of the kinetic energy of water falling from a $210 \ m$ high waterfall is converted into heat,the rise in temperature of the water at the bottom of the fall is nearly (specific heat of water $= 4.2 \times 10^3 \ J \ kg^{-1} \ K^{-1}$ and $g = 10 \ m/s^2$):

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