CH_3COOH xrightarrow{LiAlH_4} AA + CH_3COOH x | vedclass

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(D) Step $1$: Reduction of acetic acid $(CH_3COOH)$ with $LiAlH_4$ is a strong reducing agent that reduces carboxylic acids to primary alcohols.$CH_3C

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$C_2H_5OH, CH_3COOC_2H_5$

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(D) Step $1$: Reduction of acetic acid $(CH_3COOH)$ with $LiAlH_4$ is a strong reducing agent that reduces carboxylic acids to primary alcohols.$CH_3COOH + 4[H] \xrightarrow{LiAlH_4} CH_3CH_2OH + H_2O$Thus,$A$ is ethanol $(C_2H_5OH)$.Step $2$: Esterification reaction between ethanol $(A)$ and acetic acid $(CH_3COOH)$ in the presence of an acid catalyst $(H_3O^+)$ yields an ester.$CH_3CH_2OH + CH_3COOH \xrightarrow{H_3O^+} CH_3COOC_2H_5 + H_2O$Thus,$B$ is ethyl acetate $(CH_3COOC_2H_5)$.Therefore,$A = C_2H_5OH$ and $B = CH_3COOC_2H_5$.

Column-$I$	Column-$II$
$(i)$ Acetic acid	$(a)$ Stephen
$(ii)$ Sodium phenate	$(b)$ Friedel-Crafts
$(iii)$ Methyl cyanide	$(c)$ $HVZ$
$(iv)$ Toluene	$(d)$ Kolbe's

$CH_3COOH \xrightarrow{LiAlH_4} A$
$A + CH_3COOH \xrightarrow{H_3O^+} B + H_2O$
In the above reactions,'$A$' and '$B$' respectively are:

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Choose the correct option$(s)$ for the following reaction sequence. Consider $Q$,$R$ and $S$ as major products.

Match the reactant in Column-$I$ with the reaction in Column-$II$:
Column-$I$ Column-$II$
$(i)$ Acetic acid $(a)$ Stephen
$(ii)$ Sodium phenate $(b)$ Friedel-Crafts
$(iii)$ Methyl cyanide $(c)$ $HVZ$
$(iv)$ Toluene $(d)$ Kolbe's

Arrange the following labelled hydrogens in decreasing order of acidity.

$(i) \ F_3CCOOH$
$(ii) \ CH_3COOH$
$(iii) \ C_6H_5COOH$
$(iv) \ CH_3CH_2COOH$
Correct order of $pK_a$ value is:

Give the conversion of the following:
$(i)$ Phthalimide from $o-xylene$
$(ii)$ Ethanol from Ethanoic anhydride

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$CH_3COOH \xrightarrow{LiAlH_4} A$$A + CH_3COOH \xrightarrow{H_3O^+} B + H_2O$In the above reactions,'$A$' and '$B$' respectively are: