$A$ conducting wire bent in the shape of a semicircle has length $L$ and moves in its plane with constant velocity $v$. $A$ uniform magnetic field $B$ exists in the direction perpendicular to the plane of the wire. The velocity makes an angle $45^{\circ}$ to the diameter joining the free ends,and the emf induced between the ends of the wire is $\Phi = \alpha(B v L)$. The value of the constant $\alpha$ is

  • A
    $\sqrt{2}$
  • B
    $\frac{2}{\pi}$
  • C
    $\frac{1}{\sqrt{2}}$
  • D
    $\frac{\sqrt{2}}{\pi}$

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