A particular reaction has a rate constant 1.1 | vedclass

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Question

(B) The unit of the rate constant $k$ is $s^{-1}$, which indicates that the reaction is a first-order reaction.
For a first-order reaction, the rate

Vedclass · Accepted Answer

$603$

Vedclass · Answer

(B) The unit of the rate constant $k$ is $s^{-1}$, which indicates that the reaction is a first-order reaction.
For a first-order reaction, the rate constant equation is given by:
$k = \frac{2.303}{t} \log \frac{[A]_0}{[A]_t}$
Given:
$k = 1.15 	imes 10^{-3} \,s^{-1}$
$[A]_0 = 6 \,g$
$[A]_t = 3 \,g$
Substituting the values:
$1.15 	imes 10^{-3} = \frac{2.303}{t} \log \frac{6}{3}$
$1.15 	imes 10^{-3} = \frac{2.303}{t} \log 2$
Using $\log 2 = 0.301$:
$t = \frac{2.303 	imes 0.301}{1.15 	imes 10^{-3}}$
$t = \frac{0.6932}{1.15 	imes 10^{-3}}$
$t \approx 602.8 \,s \approx 603 \,s$

$A$ particular reaction has a rate constant $1.15 \times 10^{-3} \,s^{-1}$. How long does it take for $6 \,g$ of the reactant to reduce to $3 \,g$ (in $\,s$)? $(\log 2 = 0.301)$

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