A moving coil galvanometer of resistance 100 | vedclass

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Question

(C) Given:Resistance of the galvanometer,$G = 100 \ \Omega$.Full-scale deflection current of the galvanometer,$I_g = 100 \ \mu A = 100 	imes 10^{-6}

Vedclass · Accepted Answer

$\frac{100}{9}$

Vedclass · Answer

(C) Given:Resistance of the galvanometer,$G = 100 \ \Omega$.Full-scale deflection current of the galvanometer,$I_g = 100 \ \mu A = 100 	imes 10^{-6} \ A = 0.1 	imes 10^{-3} \ A$.Total current to be measured,$I = 1 \ mA = 1 	imes 10^{-3} \ A$.To convert a galvanometer into an ammeter,a shunt resistance $S$ is connected in parallel with the galvanometer.The formula for shunt resistance is:$S = \frac{I_g G}{I - I_g}$Substituting the values:$S = \frac{0.1 	imes 10^{-3} 	imes 100}{1 	imes 10^{-3} - 0.1 	imes 10^{-3}}$$S = \frac{0.1 	imes 10^{-1}}{0.9 	imes 10^{-3}}$$S = \frac{10^{-2}}{0.9 	imes 10^{-3}} = \frac{10}{0.9} = \frac{100}{9} \ \Omega$.

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