${ }^{15}P_8 = A + 8 \cdot { }^{14}P_7 \Rightarrow A = $

  • A
    ${ }^{14}P_6$
  • B
    ${ }^{14}P_8$
  • C
    ${ }^{15}P_7$
  • D
    ${ }^{16}P_9$

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