$\sum_{r=0}^{10} {}^{40-r} C_5$ is equal to

  • A
    ${}^{41} C_5 - {}^{30} C_5$
  • B
    ${}^{41} C_6 - {}^{30} C_6$
  • C
    ${}^{41} C_5 + {}^{30} C_5$
  • D
    ${}^{41} C_6$

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Similar Questions

$C_0 C_r + C_1 C_{r+1} + C_2 C_{r+2} + \dots + C_{n-r} C_n =$

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If $(1 + x + x^2)^n = a_0 + a_1x + a_2x^2 + \dots + a_{2n}x^{2n}$,then $a_0 + a_3 + a_6 + \dots =$

If $(1 + x)^n = C_0 + C_1x + C_2x^2 + .... + C_nx^n$,then the value of $C_0 + 2C_1 + 3C_2 + .... + (n + 1)C_n$ will be

If $(1 + x)^{15} = C_0 + C_1x + C_2x^2 + ...... + C_{15}x^{15},$ then $C_2 + 2C_3 + 3C_4 + .... + 14C_{15} = $

Match the expressions in List-$I$ with their values in List-$II$ for the expansion $(1+x+x^2)^n = a_0 + a_1 x + a_2 x^2 + \ldots + a_{2n} x^{2n}$.
List-$I$List-$II$
$(A)$ $a_0 + a_2 + \ldots + a_{2n}$$(I)$ $n \cdot 3^{n-1}$
$(B)$ $a_1 + a_3 + \ldots + a_{2n-1}$$(II)$ $n \cdot 3^n$
$(C)$ $a_1 + 2a_2 + 3a_3 + \ldots + 2n a_{2n}$$(III)$ $\frac{1}{2}(3^n + 1)$
$(IV)$ $\frac{1}{2}(3^n - 1)$

The correct match is:

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