$A$ satellite revolving around the earth at a certain height experiences acceleration due to gravity equal to $\frac{16}{49} g_0$,where $g_0$ is the acceleration due to gravity on the earth's surface. If $R$ is the radius of earth,then the square of time period of the satellite's revolution is equal to $K\left[\frac{\pi^2 R^3}{G M}\right]$. The value of $K$ is

  • A
    $\frac{27}{36}$
  • B
    $\frac{343}{16}$
  • C
    $\frac{125}{64}$
  • D
    $\frac{675}{81}$

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