$\frac{d}{d x}\left[\left(x^{\frac{5}{2}}-x^{\frac{3}{2}}+1\right)\left(x^2-3 x+5\right)\right]=$

  • A
    $\frac{9}{2} x^{\frac{7}{2}}-14 x^{\frac{5}{2}}+20 x^{\frac{3}{2}}-\frac{15}{2} x^{\frac{1}{2}}+2 x-3$
  • B
    $\frac{9}{2} x^{\frac{7}{2}}-7 x^{\frac{5}{2}}+5 x^{\frac{3}{2}}-\frac{3}{2} x^{\frac{1}{2}}+2 x-3$
  • C
    $9 x^{\frac{7}{2}}-14 x^{\frac{5}{2}}+20 x^{\frac{3}{2}}-15 x^{\frac{1}{2}}+2 x-3$
  • D
    $\frac{9}{2} x^{\frac{7}{2}}-\frac{7}{2} x^{\frac{5}{2}}+\frac{5}{2} x^{\frac{3}{2}}-\frac{15}{2} x^{\frac{1}{2}}+2 x-3$

Explore More

Similar Questions

यदि $f(x)=3 x^2+2 x f^{\prime}(1)+f^{\prime \prime}(2)$ है,तो $f(x)=$ . . . . . .

यदि $f(x) = \sqrt{1 + \cos^2(x^2)}$ है,तो $f'\left(\frac{\sqrt{\pi}}{2}\right)$ का मान ज्ञात कीजिए।

Difficult
View Solution

यदि $y = \sqrt{\frac{1 + \tan x}{1 - \tan x}}$ है,तो $\frac{dy}{dx} = $

निम्नलिखित फलन का अवकलज ज्ञात कीजिए: $\frac{\sec x-1}{\sec x+1}$

$x$ के सापेक्ष फलन का अवकलन कीजिए: $\sin^{-1}(x\sqrt{x})$,जहाँ $0 \le x \le 1$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo