A constant horizontal force overrightarrow{F} | vedclass

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Question

(A) First, calculate the mass of block $A$ using Newton's second law: $F = m_A a \Rightarrow 10 = m_A 	imes 20 \Rightarrow m_A = 0.5 \,kg$. When bloc

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(A) First, calculate the mass of block $A$ using Newton's second law: $F = m_A a \Rightarrow 10 = m_A 	imes 20 \Rightarrow m_A = 0.5 \,kg$. When block $A$ is placed against block $B$ and a force $F^{\prime} = 20 \,N$ is applied, both blocks move together with a common acceleration $a$. The equation of motion for block $A$ is: $F^{\prime} - N = m_A a \Rightarrow 20 - N = 0.5 a$ $(i)$. The equation of motion for block $B$ is: $N = m_B a \Rightarrow N = 1.5 a$ $(ii)$. Adding equations $(i)$ and $(ii)$: $20 = 2 a \Rightarrow a = 10 \,m/s^2$. Substituting $a$ into equation $(ii)$: $N = 1.5 	imes 10 = 15 \,N$. Thus, the force on block $B$ is $15 \,N$.

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