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(D) Let $m_1 = 5 \,kg$ and $m_2 = 3 \,kg$. The system is accelerating upwards with $a = 2 \,m/s^2$.For the lower mass $m_2$ $(3 \,kg)$:The forces acti

Vedclass · Accepted Answer

$94.4$

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(D) Let $m_1 = 5 \,kg$ and $m_2 = 3 \,kg$. The system is accelerating upwards with $a = 2 \,m/s^2$.For the lower mass $m_2$ $(3 \,kg)$:The forces acting are tension $T_2$ upwards and weight $m_2 g$ downwards.The equation of motion is: $T_2 - m_2 g = m_2 a$$T_2 - 3 	imes 9.8 = 3 	imes 2$$T_2 - 29.4 = 6$$T_2 = 35.4 \,N$For the upper mass $m_1$ $(5 \,kg)$:The forces acting are tension $T_1$ upwards, and tension $T_2$ and weight $m_1 g$ downwards.The equation of motion is: $T_1 - T_2 - m_1 g = m_1 a$$T_1 - 35.4 - 5 	imes 9.8 = 5 	imes 2$$T_1 - 35.4 - 49 = 10$$T_1 - 84.4 = 10$$T_1 = 94.4 \,N$

Two masses of $5 \,kg$ and $3 \,kg$ are suspended with the help of massless inextensible strings as shown in the figure below. When the whole system is moving upwards with an acceleration of $2 \,m/s^2$, the value of $T_1$ is (use $g = 9.8 \,m/s^2$): (in $\,N$)

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