$A$ square loop of length $L$ is placed with its edges parallel to the $XY$-axes. The loop carries a current $I$. If the magnetic field in the region varies as $B = B_0 \left(1 + \frac{xy}{L^2}\right) \hat{k}$, then the magnitude of the net force on the loop will be:

  • A
    $\frac{\sqrt{26}}{2} I B_0 L$
  • B
    $2 I B_0 L$
  • C
    $\frac{I B_0 L}{2}$
  • D
    $0$

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