What is the net force on the loop shown in th | vedclass

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(A) The force on a current-carrying wire due to another parallel wire is given by $F = \frac{\mu_0 I_1 I_2 L}{2 \pi r}$.For the side $AB$ (at distance

Vedclass · Accepted Answer

$25 	imes 10^{-7} \, N$ towards the left

Vedclass · Answer

(A) The force on a current-carrying wire due to another parallel wire is given by $F = \frac{\mu_0 I_1 I_2 L}{2 \pi r}$.For the side $AB$ (at distance $r_1 = 2 \, cm = 2 	imes 10^{-2} \, m$):$F_{AB} = \frac{2 	imes 10^{-7} 	imes 2 	imes 1 	imes 15 	imes 10^{-2}}{2 	imes 10^{-2}} = 30 	imes 10^{-7} \, N$ (Attractive,towards the left).For the side $CD$ (at distance $r_2 = 2 \, cm + 10 \, cm = 12 \, cm = 12 	imes 10^{-2} \, m$):$F_{CD} = \frac{2 	imes 10^{-7} 	imes 2 	imes 1 	imes 15 	imes 10^{-2}}{12 	imes 10^{-2}} = 5 	imes 10^{-7} \, N$ (Repulsive,towards the right).The net force is $F_{net} = F_{AB} - F_{CD} = 30 	imes 10^{-7} - 5 	imes 10^{-7} = 25 	imes 10^{-7} \, N$ towards the left.

What is the net force on the loop shown in the figure?

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