$A$ person walks along a straight road from his house to a market $2.5 \,km$ away with a speed of $5 \,km/h$ and instantly turns back and reaches his house with a speed of $7.5 \,km/h$. The average speed of the person during the time interval $0$ to $50 \,min$ is (in $m/s$)
- A$4 \frac{2}{3}$
- B$\frac{5}{3}$
- C$\frac{5}{6}$
- D$\frac{1}{3}$
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