A body has speeds V,2V,and 3V in the first 1/ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The average speed is defined as the total distance divided by the total time taken.Let the total distance be $S$.The distance for each segment is

Vedclass · Accepted Answer

$\frac{18}{11}V$

Vedclass · Answer

(C) The average speed is defined as the total distance divided by the total time taken.Let the total distance be $S$.The distance for each segment is $S/3$.The time taken for the first segment is $t_1 = \frac{S/3}{V} = \frac{S}{3V}$.The time taken for the second segment is $t_2 = \frac{S/3}{2V} = \frac{S}{6V}$.The time taken for the third segment is $t_3 = \frac{S/3}{3V} = \frac{S}{9V}$.Total time $T = t_1 + t_2 + t_3 = \frac{S}{3V} + \frac{S}{6V} + \frac{S}{9V}$.Taking the common denominator as $18V$,we get $T = \frac{6S + 3S + 2S}{18V} = \frac{11S}{18V}$.Average speed $V_{av} = \frac{S}{T} = \frac{S}{11S / 18V} = \frac{18V}{11}$.

$A$ body has speeds $V$,$2V$,and $3V$ in the first $1/3$ of distance $S$,the second $1/3$ of distance $S$,and the third $1/3$ of distance $S$ respectively. Its average speed will be:

Similar Questions

$A$ particle moves with constant speed $v$ along a regular hexagon $ABCDEF$ in the same order. What is the magnitude of the average velocity for its motion from $A$ to $F$?

$A$ vehicle runs on a straight road of length $L$. It travels half the distance with speed $V$ and the remaining distance with speed $\frac{V}{3}$. Its average speed is

Which information cannot be drawn from average velocity?

$A$ body has speed $V, 2V$ and $3V$ in the first $1/3$ of distance $S$,second $1/3$ of $S$,and third $1/3$ of $S$ respectively. Its average speed will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module