$A$ small-angled prism is made of a material of refractive index $\frac{3}{2}$. The ratio of the angles of minimum deviation when the prism is placed in air and in water of refractive index $\frac{4}{3}$ is:

$A$ ray of light is incident normally on a prism of refractive index $1.5$,as shown. The prism is immersed in a liquid of refractive index $\mu$. The largest value of the angle $ACB$ such that the ray is totally internally reflected at the face $AC$ is $30^o$. Then the value of $\mu$ must be :

$A$ glass prism deviates the red and violet rays through $9^{\circ}$ and $11^{\circ}$ respectively. $A$ second prism of equal angle deviates them through $11^{\circ}$ and $13^{\circ}$ respectively. The ratio of dispersive power of the second prism to the first prism is

If the angle of prism is $60^o$ and the angle of minimum deviation is $40^o$,the angle of refraction will be.....$^o$

$A$ light ray is incident upon a prism in minimum deviation position and suffers a deviation of $34^o$. If the shaded half of the prism is removed,the ray will

In the given figure,the face $AC$ of the equilateral prism is immersed in a liquid of refractive index $n$. For an incident angle of $60^{\circ}$ at the side $AC$,the refracted light beam just grazes along the face $AC$. The refractive index of the liquid is $n = \frac{\sqrt{x}}{4}$. The value of $x$ is (Given refractive index of glass $= 1.5$)