A balance is made using a uniform metre scale | vedclass

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(D) Let the mass of the scale be $M = 100 \ g$ acting at its center of mass $(50 \ cm)$. Let the mass of each plate be $m = 200 \ g$ at $0 \ cm$ and $

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$100$

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(D) Let the mass of the scale be $M = 100 \ g$ acting at its center of mass $(50 \ cm)$. Let the mass of each plate be $m = 200 \ g$ at $0 \ cm$ and $100 \ cm$. The pivot is at $x = 45 \ cm$.Taking moments about the pivot at $45 \ cm$:Clockwise moments: $M_{veg} 	imes (100 - 45) + m 	imes (100 - 45) + M 	imes (50 - 45) = 300 	imes (45 - 0) + m 	imes (45 - 0)$$M_{veg} 	imes 55 + 200 	imes 55 + 100 	imes 5 = 300 	imes 45 + 200 	imes 45$$55 M_{veg} + 11000 + 500 = 13500 + 9000$$55 M_{veg} + 11500 = 22500$$55 M_{veg} = 11000$$M_{veg} = 200 \ g$.The actual weight is $300 \ g$ and the measured weight is $200 \ g$. The error is $|300 - 200| = 100 \ g$.

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