(D) Given: Area $A = 1.0 \,m^2$, Thickness $l = 3 \,cm = 0.03 \,m$, Temperature difference $\Delta \theta = 30^{\circ} C - 0^{\circ} C = 30^{\circ} C$

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(D) Given: Area $A = 1.0 \,m^2$, Thickness $l = 3 \,cm = 0.03 \,m$, Temperature difference $\Delta \theta = 30^{\circ} C - 0^{\circ} C = 30^{\circ} C$, Thermal conductivity $K = 0.03 \,W/mK$, Latent heat $L = 3.00 \times 10^5 \,J/kg$, Time $t = 24 \times 3600 \,s = 86400 \,s$.Using the heat conduction formula: $Q = \frac{K A \Delta \theta t}{l}$.Since $Q = m L$, we have $m = \frac{K A \Delta \theta t}{L l}$.Substituting the values: $m = \frac{0.03 \times 1.0 \times 30 \times 86400}{3.00 \times 10^5 \times 0.03}$.$m = \frac{0.9 \times 86400}{9000} = \frac{77760}{9000} = 8.64 \,kg$.

Class 11 Physics 10-2.Heat Transfer Heat Conduction and Thermal Conductivity

Difficult

$A$ thermocol box has a total wall area (including the lid) of $1.0 \,m^2$ and wall thickness of $3 \,cm$. It is filled with ice at $0^{\circ} C$. If the average temperature outside the box is $30^{\circ} C$ throughout the day, the amount of ice that melts in one day is (Given: $K_{\text{thermocol}} = 0.03 \,W/mK$, $L_{\text{fusion(ice)}} = 3.00 \times 10^5 \,J/kg$) (in $\,kg$)

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A
$1$
B
$2.88$
C
$25.92$
D
$8.64$

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10-2.Heat Transfer

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Heat Conduction and Thermal Conductivity

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Heat is conducted across a composite block of two slabs of thickness $d$ and $2d$. Their thermal conductivities are $2k$ and $k$ respectively. All the heat entering the face $AB$ leaves from the face $CD$. The temperature in $^oC$ of the junction $EF$ of the two slabs is:

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The ratio of the diameters of two metallic rods of the same material is $2 : 1$ and their lengths are in the ratio $1 : 4$. If the temperature difference between their ends is equal,the rate of flow of heat in them will be in the ratio: (in $:1$)

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$A$ metal rod of length $2\, m$ has cross-sectional areas $2A$ and $A$ as shown in the figure. The two ends are maintained at temperatures $100\,^{\circ}C$ and $70\,^{\circ}C$. The temperature of the junction point $C$ is ........ $^{\circ}C$.

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For cooking the food,which of the following type of utensil is most suitable?

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$A$ wall consists of two layers $A$ and $B$. The two layers have the same thickness but are made of different materials. The thermal conductivity of $A$ is twice that of $B$. Under steady-state conditions,the temperature difference between the two ends is $36 ^\circ C$. The temperature difference across the two surfaces of $A$ is .......... $^\circ C$.

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Heat is conducted across a composite block of two slabs of thickness $d$ and $2d$. Their thermal conductivities are $2k$ and $k$ respectively. All the heat entering the face $AB$ leaves from the face $CD$. The temperature in $^oC$ of the junction $EF$ of the two slabs is:

The ratio of the diameters of two metallic rods of the same material is $2 : 1$ and their lengths are in the ratio $1 : 4$. If the temperature difference between their ends is equal,the rate of flow of heat in them will be in the ratio: (in $:1$)

$A$ metal rod of length $2\, m$ has cross-sectional areas $2A$ and $A$ as shown in the figure. The two ends are maintained at temperatures $100\,^{\circ}C$ and $70\,^{\circ}C$. The temperature of the junction point $C$ is ........ $^{\circ}C$.

For cooking the food,which of the following type of utensil is most suitable?

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