A force F = (2 hat{i} + 4 hat{j}) text{ N} is | vedclass

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(C) The displacement of the object is along the $X$-axis by $3 	ext{ m}$, so the displacement vector is $\vec{d} = 3 \hat{i} 	ext{ m}$.Given the for

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$6$

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(C) The displacement of the object is along the $X$-axis by $3 	ext{ m}$, so the displacement vector is $\vec{d} = 3 \hat{i} 	ext{ m}$.Given the force vector is $\vec{F} = (2 \hat{i} + 4 \hat{j}) 	ext{ N}$.The work done $W$ by a constant force is given by the dot product of the force vector and the displacement vector:$W = \vec{F} \cdot \vec{d}$$W = (2 \hat{i} + 4 \hat{j}) \cdot (3 \hat{i})$$W = (2 	imes 3)(\hat{i} \cdot \hat{i}) + (4 	imes 0)(\hat{j} \cdot \hat{i})$Since $\hat{i} \cdot \hat{i} = 1$ and $\hat{j} \cdot \hat{i} = 0$, we get:$W = 6 	imes 1 + 0 = 6 	ext{ J}$.

$A$ force $F = (2 \hat{i} + 4 \hat{j}) \text{ N}$ is applied on an object of mass $M$. What is the work done by this force in moving the object horizontally along the $X$-axis by $3 \text{ m}$ (in $\text{ J}$)?

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