mathop {lim }limits_{x to 0} frac{{sin {x^cir | vedclass

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Question

(B) हम जानते हैं कि $x^\circ = \frac{\pi x}{180} 	ext{ रेडियन}$.अतः,$\mathop {\lim }\limits_{x 	o 0} \frac{{\sin {x^\circ}}}{x} = \mathop {\lim }\li

Vedclass · Accepted Answer

$\frac{\pi}{180}$

Vedclass · Answer

(B) हम जानते हैं कि $x^\circ = \frac{\pi x}{180} 	ext{ रेडियन}$.अतः,$\mathop {\lim }\limits_{x 	o 0} \frac{{\sin {x^\circ}}}{x} = \mathop {\lim }\limits_{x 	o 0} \frac{{\sin \left( \frac{\pi x}{180} ight)}}{x}$.$\frac{\pi}{180}$ से गुणा और भाग करने पर,हमें प्राप्त होता है:$\mathop {\lim }\limits_{x 	o 0} \left( \frac{\pi}{180} ight) \cdot \frac{{\sin \left( \frac{\pi x}{180} ight)}}{\frac{\pi x}{180}}$.चूंकि $\mathop {\lim }\limits_{	heta 	o 0} \frac{\sin 	heta}{	heta} = 1$,इसलिए व्यंजक $\frac{\pi}{180} \cdot 1 = \frac{\pi}{180}$ हो जाता है।

$\mathop {\lim }\limits_{x \to 0} \frac{{\sin {x^\circ}}}{x} = $

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