A radioactive atom ^X_Y M emits two alpha par | vedclass

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(B) The initial atom is $^X_Y M$.$1$. Emission of first $\alpha$ particle $(^4_2 He)$: The mass number decreases by $4$ and atomic number decreases by

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$X-Y-5$

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(B) The initial atom is $^X_Y M$.$1$. Emission of first $\alpha$ particle $(^4_2 He)$: The mass number decreases by $4$ and atomic number decreases by $2$. Product: $^{X-4}_{Y-2} N$.$2$. Emission of second $\alpha$ particle: The mass number decreases by $4$ and atomic number decreases by $2$. Product: $^{X-8}_{Y-4} O$.$3$. Emission of one $\beta$ particle $(^0_{-1} e)$: The mass number remains unchanged and atomic number increases by $1$. Product: $^{X-8}_{Y-3} P$.Number of neutrons = Mass number - Atomic number.Number of neutrons = $(X-8) - (Y-3) = X - 8 - Y + 3 = X - Y - 5$.

$A$ radioactive atom $^X_Y M$ emits two $\alpha$ particles and one $\beta$ particle successively. The number of neutrons in the nucleus of the product will be

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