mathop {lim }limits_{x to 0} frac{{sin 3x + s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) We are given the limit: $\mathop {\lim }\limits_{x 	o 0} \frac{{\sin 3x + \sin x}}{x}$.Using the property of limits,we can split the expression:$

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(C) We are given the limit: $\mathop {\lim }\limits_{x 	o 0} \frac{{\sin 3x + \sin x}}{x}$.Using the property of limits,we can split the expression:$= \mathop {\lim }\limits_{x 	o 0} \frac{\sin 3x}{x} + \mathop {\lim }\limits_{x 	o 0} \frac{\sin x}{x}$.Multiply and divide the first term by $3$:$= \mathop {\lim }\limits_{x 	o 0} 3 \cdot \frac{\sin 3x}{3x} + \mathop {\lim }\limits_{x 	o 0} \frac{\sin x}{x}$.Using the standard limit $\mathop {\lim }\limits_{	heta 	o 0} \frac{\sin 	heta}{	heta} = 1$:$= 3(1) + 1 = 3 + 1 = 4$.

$\mathop {\lim }\limits_{x \to 0} \frac{{\sin 3x + \sin x}}{x} = $

Similar Questions

The value of $\mathop {\lim }\limits_{x \to 0} \frac{(1 - \cos 2x)\sin 5x}{x^2 \sin 3x}$ is

$\lim _{x \rightarrow \pi} \frac{1-\sin (x/2)}{\left(\cos \frac{x}{2}\right)\left(\cos \frac{x}{4}-\sin \frac{x}{4}\right)} =$

$\mathop {\lim }\limits_{x \to 0} \frac{{{x^2} - \tan 2x}}{{\tan x}} = $

The value of $\mathop {\lim }\limits_{\theta \to 0} \left( \frac{\sin(\theta/4)}{\theta} \right)$ is

$\lim _{x \rightarrow 0} \frac{\tan ^3 x - \sin ^3 x}{x^5}$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module