$A$ fair six-faced die is rolled $12$ times. The probability that each face turns up exactly twice is equal to:

  • A
    $\frac{12!}{6!6!6^{12}}$
  • B
    $\frac{2^{12}}{2^{6} 6^{12}}$
  • C
    $\frac{12!}{2^{6} 6^{12}}$
  • D
    $\frac{12!}{6^{2} 6^{12}}$

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