If a random variable $X$ has the probability distribution given by $P(X=0)=3C^3$,$P(X=2)=5C-10C^2$ and $P(X=4)=4C-1$,then the variance of that distribution is

  • A
    $\frac{68}{9}$
  • B
    $\frac{22}{9}$
  • C
    $\frac{612}{81}$
  • D
    $\frac{128}{81}$

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