A population of diploid organisms is at Hardy | vedclass

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(A) According to the Hardy-Weinberg principle, for a gene with two alleles $A$ and $a$, let the frequency of allele $A$ be $p$ and the frequency of al

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$0.01$

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(A) According to the Hardy-Weinberg principle, for a gene with two alleles $A$ and $a$, let the frequency of allele $A$ be $p$ and the frequency of allele $a$ be $q$.Given that the frequency of allele $A$ $(p)$ is $0.1$.The frequency of the homozygous dominant genotype $AA$ is given by $p^2$.Therefore, the frequency of $AA = (0.1)^2 = 0.01$.Thus, the correct option is $A$.

$A$ population of diploid organisms is at Hardy-Weinberg equilibrium. If the frequency of allele $A$ is $0.1$, the frequency of $AA$ is . . . . . . .

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