$A$ particle completes $2$ revolutions in a circular path of radius $3$ cm. The angular displacement of the particle will be (in radian) (in $\pi$)

When a particle moves in a uniform circular motion,it has:

$A$ particle revolves around a circular path. The acceleration of the particle is

For a particle executing uniform circular motion:

$A$ particle moves in the $x-y$ plane according to the rules $x = a \sin \omega t$ and $y = a \cos \omega t$. The particle follows:

For a particle in uniform circular motion,the acceleration $\vec{a}$ at any point $P (R, \theta)$ on the circular path of radius $R$ is (when $\theta$ is measured from the positive $x$-axis and $v$ is uniform speed):