$A$ black body emits radiation of maximum intensity of wavelength '$\lambda$' at temperature '$T$' $K$. Its corresponding wavelength at temperature $(2.5T)$ $K$ will be

If the wavelengths of maximum intensity of radiation emitted by two black bodies $A$ and $B$ are $0.5 \mu m$ and $0.1 \ mm$ respectively,then the ratio of the temperatures of the bodies $A$ and $B$ is

$A$ black body has a maximum wavelength $\lambda_{m}$ at a temperature of $2200 \ K$. Its corresponding wavelength at a temperature of $3300 \ K$ will be:

The temperature of a furnace is $2000^\circ C$ and the wavelength of maximum intensity in its spectrum is $4000 \ \mathring{A}$. If the wavelength of maximum intensity is $2000 \ \mathring{A}$, calculate the temperature of the furnace in $^\circ C$.

Ordinary bodies $A$ and $B$ radiate maximum energy at wavelengths differing by $4 \mu m$. The absolute temperature of body $A$ is $3$ times that of body $B$. The wavelength at which body $B$ radiates maximum energy is: (in $\mu m$)

Which one of the following is the $\nu_{m}-T$ graph for a perfectly black body? Here, $\nu_{m}$ is the frequency of radiation with maximum intensity and $T$ is the absolute temperature.