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(D) The magnetic field $B$ at a perpendicular distance $r$ from a long straight wire carrying current $I$ is given by the formula:$B = \frac{\mu_0 I}{

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$5 : 2$

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(D) The magnetic field $B$ at a perpendicular distance $r$ from a long straight wire carrying current $I$ is given by the formula:$B = \frac{\mu_0 I}{2 \pi r}$From this formula, we can see that $B \propto \frac{1}{r}$.Let $B_1$ be the magnetic field at distance $r_1 = 2 	ext{ cm}$ and $B_2$ be the magnetic field at distance $r_2 = 5 	ext{ cm}$.Then, the ratio $\frac{B_1}{B_2} = \frac{r_2}{r_1}$.Substituting the given values:$\frac{B_1}{B_2} = \frac{5}{2} = 5 : 2$.Therefore, the ratio of the magnetic field at $2 	ext{ cm}$ and $5 	ext{ cm}$ is $5 : 2$.

$A$ straight long wire is carrying current $I$. The ratio of magnetic field due to this wire at perpendicular distance $2 \text{ cm}$ and $5 \text{ cm}$ respectively from the wire is

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