$A$ square loop of area $25 \ cm^2$ has a resistance of $10 \ \Omega$. The loop is placed in a uniform magnetic field of magnitude $40 \ T$. The plane of the loop is perpendicular to the magnetic field. The work done in pulling the loop out of the magnetic field slowly and uniformly in $1 \ s$ will be:

  • A
    $2.5 \times 10^{-3} \ J$
  • B
    $1.0 \times 10^{-3} \ J$
  • C
    $1.0 \times 10^{-4} \ J$
  • D
    $5 \times 10^{-3} \ J$

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