$A$ transformer has $120$ turns in the primary coil and carries $5 \text{ A}$ current. Input power is $1 \text{ kW}$. To have $560 \text{ V}$ output, the number of turns in the secondary coil will be:

If the primary coil of a transformer has $100$ turns and the secondary has $200$ turns,then for an input of $220 \ V$ at $10 \ A$,the output current in the step-up transformer will be . . . . . . . (in $A$)

$A$ $12\,V, 60\,W$ lamp is connected to the secondary of a step-down transformer, whose primary is connected to $AC$ mains of $220\,V$. Assuming the transformer to be ideal, the current in the primary winding is $..........\,A$.

Find the current through the primary coil $(P)$ of the transformer shown below. (in $A$)

In an ideal transformer,the turns ratio is $\frac{N_p}{N_S} = \frac{1}{2}$. The ratio $V_s : V_p$ is equal to (the symbols carry their usual meaning):

$A$ transformer is employed to reduce $220\, V$ to $11\, V$. The primary draws a current of $5\, A$ and the secondary $90\, A$. The efficiency of the transformer is......$\%$